# Line slope calculator x+4y=28

**Straight line given by points A[4; 6] and B[8; 5]**

## Calculation:

**Slope-intercept form of line:**y = -0.25x+7

**Canonical form of the line equation:**x+4y-28 = 0

**Parametric form of the line equation:**

x = 4t+4

y = -t+6 ; t ∈ R

**Slope:**m = -0.25

**Slope angle of line: φ =**-14°2'10″ = -0.245 rad

**X intercept:**x

_{0}= 28

**Y intercept:**y

_{0}= q = 7

**Distance line from the origin:**d

_{0}= 6.791

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(4; -1)

**Normal vector: n =**(1; 4)

**Midpoint of the segment AB: M =**[6; 5.5]

**Perpendicular Bisector equation:**4x-y-18.5 = 0

**Vector OA = (4; 6) ; |OA| = 7.2111**

**Vector OB = (8; 5) ; |OB| = 9.434**

**Scalar product OA .OB = 62**

**Angle ∠ AOB = 24°18'16″ = 0.4242 rad**